Integrand size = 20, antiderivative size = 66 \[ \int \frac {x^m \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {B x^{1+m}}{b (1+m)}+\frac {(A b-a B) x^{1+m} \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},-\frac {b x^2}{a}\right )}{a b (1+m)} \]
[Out]
Time = 0.02 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {470, 371} \[ \int \frac {x^m \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {x^{m+1} (A b-a B) \operatorname {Hypergeometric2F1}\left (1,\frac {m+1}{2},\frac {m+3}{2},-\frac {b x^2}{a}\right )}{a b (m+1)}+\frac {B x^{m+1}}{b (m+1)} \]
[In]
[Out]
Rule 371
Rule 470
Rubi steps \begin{align*} \text {integral}& = \frac {B x^{1+m}}{b (1+m)}-\frac {(-A b (1+m)+a B (1+m)) \int \frac {x^m}{a+b x^2} \, dx}{b (1+m)} \\ & = \frac {B x^{1+m}}{b (1+m)}+\frac {(A b-a B) x^{1+m} \, _2F_1\left (1,\frac {1+m}{2};\frac {3+m}{2};-\frac {b x^2}{a}\right )}{a b (1+m)} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.83 \[ \int \frac {x^m \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {x^{1+m} \left (a B+(A b-a B) \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},-\frac {b x^2}{a}\right )\right )}{a b (1+m)} \]
[In]
[Out]
\[\int \frac {x^{m} \left (x^{2} B +A \right )}{b \,x^{2}+a}d x\]
[In]
[Out]
\[ \int \frac {x^m \left (A+B x^2\right )}{a+b x^2} \, dx=\int { \frac {{\left (B x^{2} + A\right )} x^{m}}{b x^{2} + a} \,d x } \]
[In]
[Out]
Result contains complex when optimal does not.
Time = 1.80 (sec) , antiderivative size = 187, normalized size of antiderivative = 2.83 \[ \int \frac {x^m \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {A m x^{m + 1} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{4 a \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {A x^{m + 1} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{4 a \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {B m x^{m + 3} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {3}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )}{4 a \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )} + \frac {3 B x^{m + 3} \Phi \left (\frac {b x^{2} e^{i \pi }}{a}, 1, \frac {m}{2} + \frac {3}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )}{4 a \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )} \]
[In]
[Out]
\[ \int \frac {x^m \left (A+B x^2\right )}{a+b x^2} \, dx=\int { \frac {{\left (B x^{2} + A\right )} x^{m}}{b x^{2} + a} \,d x } \]
[In]
[Out]
\[ \int \frac {x^m \left (A+B x^2\right )}{a+b x^2} \, dx=\int { \frac {{\left (B x^{2} + A\right )} x^{m}}{b x^{2} + a} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {x^m \left (A+B x^2\right )}{a+b x^2} \, dx=\int \frac {x^m\,\left (B\,x^2+A\right )}{b\,x^2+a} \,d x \]
[In]
[Out]